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On pointer move/copy c-style
I have a function in C++ and I am rewriting it in C. Since that function allocates memory on the stack, my plan is to just use malloc/realloc with C functions (I am probably going to replace all of std::vectors with C-style arrays).
The other day I came across this piece of code from :
extern “C” void *operator new(__SIZE_TYPE __size)
return ::operator new(__size);
It seems as if new is a variable-length array. I thought that data-members in C++ are not “modified” when they are copied/moved and that they are “copied” at the time of definition or initialization.
Does that function allow copying/moving of its parameters or do those just undergo move-semantics?
C++ has rules about how arguments to functions are to be passed, and the same rules also apply to member functions. A move/copy of an argument results in a move/copy of the contained members. This is mandated by the language.
A prvalue of type “pointer to cv1 B” can be explicitly converted to a prvalue of type “pointer to cv2 D”, where B and D are class types, having the same cv-unqualified version of T, and cv2 is more cv-qualified than cv1. The result of the conversion is a pointer to the cv2 D subobject of the B object (if any) pointed to by the original pointer, or null otherwise.
Thus, if foo is a member function with a T* parameter, then the copy/move of that argument involves copying the contained T, which is not allowed to be a non-POD type.
If foo is a free function taking a T* parameter, then the copy/move
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